Subject: Parse integer out of string 2005-07-07 - By Frans Verhoef
Back
Actually not J2EE, but here we go:
String yourString = "A string that contains number 30 that needs to be parsed
out";
Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher(yourString);
if(m.find()){
int yourInt = Integer.parseInt(yourString.substring(m.start(), m.end()));
}
Cheers
Frans
On Fri, 8 Jul 2005 10:26:10 +1000, Taco wrote:
>?No just one.
>
>?I found java.util.regex.Matcher but a little help would be nice,
>?I'm just a java newbie!
>
>?-- --Original Message-- --
>?From: A mailing list for Java(tm) 2 Platform, Enterprise Edition
>?[mailto:J2EE-INTEREST@(protected)] On Behalf Of Mark Galbreath
>?Sent: Friday, 8 July 2005 10:26 AM To: J2EE-INTEREST@(protected)
>?Subject: Re: Parse integer out of string
>
>?Do you have multiple integer tokens, like
>
>?BDAT 30 LAST BDAT 30 LAST
>
>??
>
>?~mark
>
>?Taco Fleur wrote:
>
>>?How do I parse an integer out of a string, for example: BDAT 30
>>?LAST
>>
>>
>>?I did not find any regex support under the String class except
>>?for matching.
>>
>>
>>?__ ____ ____ ____ ____ ____ ____
>>
>>?Taco Fleur - /E-commerce Development Manager/
>>
>>?Shelco Searches &?Services
>>
>>?An Authorised ASIC Information Broker
>>
>>?www.shelco.com.au
>>
>>?Ph: + 61 7 3236 2605
>>
>>
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