Subject: Parse integer out of string 2005-07-07 - By Frans Verhoef
Back
Just make sure that you define yourInt outside the if statement.
To be more precise:
int yourInt;
if(m.find()){
int yourInt = Integer.parseInt(yourString.substring(m.start(),m.end()));
}else{
// take your action in case no integer found in yourString
}
On Fri, 8 Jul 2005 11:21:22 +1000, Taco wrote:
>?Thanks that's sort of what I put together as well.
>
>?Using your example:
>
>?String yourString = "A string that contains number 30 that needs to
>?be parsed out";
>?Pattern p = Pattern.compile("\\d+"); Matcher m >?p.matcher(yourString); if(m
.find()) { int yourInt >?Integer.parseInt(yourString.substring(m.start(), m.end(
))); }
>?System.out.println("result: " + yourInt);
>
>?I got:
>
>?java.lang.Error: Unresolved compilation problem:
>?yourInt cannot be resolved
>
>?at SSLTransportLayer08.getResponse(SSLTransportLayer08.java:149) at
>?SSLTransportLayer08.main(SSLTransportLayer08.java:74)
>
>?Which means it never found anything.. ???
>?I'm puzzled..
>
>?-- --Original Message-- --
>?From: A mailing list for Java(tm) 2 Platform, Enterprise Edition
>?[mailto:J2EE-INTEREST@(protected)] On Behalf Of Frans Verhoef
>?Sent: Friday, 8 July 2005 11:18 AM To: J2EE-INTEREST@(protected)
>?Subject: Re: Parse integer out of string
>
>?Actually not J2EE, but here we go:
>
>?String yourString = "A string that contains number 30 that needs to
>?be parsed out"; Pattern p = Pattern.compile("\\d+"); Matcher m >?p.matcher
(yourString); if(m.find()){
>?int yourInt = Integer.parseInt(yourString.substring(m.start(),
>?m.end())); }
>
>?Cheers
>?Frans
>
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