T : Looping...

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T : Looping...

T : Looping...

2006-11-09 - By ?

Back
In my opinion , if (values[i]==searchKey) return true, the method will
return true, the last return will not execute.

Winy Wan
wanyi@(protected)

__ __

???: A mailing list for Java(tm) 2 Platform, Enterprise Edition
[mailto:J2EE-INTEREST@(protected)] ?? Emmanuel Eze
????: 2006?11?9? 18:58
???: J2EE-INTEREST@(protected)
??: Re: Looping...

I do not think that there's any problem with your approach. However, for
code neatness, I would have written it as:

public boolean find(double searchKey) {
boolean flag;
for (int i = 0; i < items; i++) {
if (values[i] == searchKey) {
flag = true;
break;
}
}
return flag;
}

Ne'Bahn wrote:

Hi list:

What are the consecuences of breaking a loop in this manner:

// items - the number of items on the array
// values - the array itself

public boolean find(double searchKey) {
for (int i = 0; i < items; i++)
if (values[i] == searchKey)
return true;
return false;
}

AFAIK when an instance leave a method all variables "dissapear" (stack
flushes, take some air, if they are objects the garbage collector prepares
for..). The fact is that I don't like to use the "break" keyword so I want
to know if this way is the same that "break, then return".

Thanks in advance.

===========================================================================
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--
Emmanuel Eze
Home Page <http://emma.ukrosoft.com> : http://emma.ukrosoft.com
With the right attitude - we can achieve the seemingly impossible!

===========================================================================
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<html xmlns:v="urn:schemas-microsoft-com:vml" xmlns:o="urn:schemas-microsoft
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<div class=Section1>

In my opinion , if  (values
[i]==searchKey)
return true, the method will return true, the last return will not execute.<o:p
></o:p>

<o:p> </o:p>

<o:p> </o:p>

<div>

Winy Wan 
<a href="mailto:wanyi@(protected)">wanyi@(protected)</a> 
 
<o:p></o:p>

<o:p> </o:p>

</div>

<div>

<div class=MsoNormal align=center style='text-align:center'>

<hr size=2 width="100%" align=center tabindex=-1>

</div>

???: A mailing list for Java(tm) 2 Platform, Enterprise
Edition [mailto:J2EE-INTEREST@(protected)] ?? Emmanuel
Eze 
????:
 <st1:chsdate IsROCDate="False" IsLunarDate="False" Day="9"
Month="11" Year="2006" w:st="on">2006?11?9
?</st1:chsdate>
18:58 
???: J2EE-INTEREST@(protected) 
??: Re: Looping...<o:p></o:p>

</div>

<o:p> </o:p>

I do not think that there's any problem
with your approach.  However, for code neatness, I would have written it
as: 
 
public boolean find(double searchKey) { 
 boolean flag; 
 for (int i = 0; i < items; i++) { 
      if (values[i] == searchKey) { 
        flag = true; 
        break; 
      } 
  } 
   return flag; 
} 
 
 
 
Ne'Bahn wrote: <o:p></o:p>

Hi list: 
 
What are the consecuences of breaking a loop in this manner: 
 
// items - the number of items on the array 
// values - the array itself 
 
public boolean find(double searchKey) { 
 for (int i = 0; i < items; i++) 
  if (values[i] == searchKey) 
   return true; 
 return false; 
} 
 
AFAIK when an instance leave a method all variables "dissapear"
(stack 
flushes, take some air, if they are objects the garbage collector prepares 
for..). The fact is that I don't like to use the "break" keyword so I
want 
to know if this way is the same that "break, then return". 
 
Thanks in advance. 
 
=========================================================================== 
To unsubscribe, send email to <a href="mailto:listserv@(protected)">listserv
@(protected)</a>
and include in the body 
of the message "signoff J2EE-INTEREST".  For general help, send
email to 
<a href="mailto:listserv@(protected)">listserv@(protected)</a> and include in
the body of the message "help". <o:p></o:p>

<o:p> </o
:p>

<div>

-- 
Emmanuel Eze 
<a href="http://emma.ukrosoft.com" title="Emmanuel Eze">Home Page</a>: <a
href="http://emma.ukrosoft.com">http://emma.ukrosoft.com</a> 
With the right attitude - we can achieve the seemingly
impossible! <o:p></o:p>

</div>

</div>

</body>

</html>
===========================================================================
To unsubscribe, send email to listserv@(protected) and include in the body
of the message "signoff J2EE-INTEREST". For general help, send email to
listserv@(protected) and include in the body of the message "help".

===========================================================================
To unsubscribe, send email to listserv@(protected) and include in the body
of the message "signoff J2EE-INTEREST". For general help, send email to
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