running! a servlet at tomcat startup 2007-11-05 - By Grzegorz Borkowski
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Johnny Kewl wrote:
>
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>
> HARBOR: http://coolharbor.100free.com/index.htm
> Now Tomcat is also a cool pojo application server
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> -- -- Original Message -- -- From: "Johnny Kewl" <john@(protected)>
> To: "Tomcat Users List" <users@(protected)>
> Sent: Monday, November 05, 2007 12:18 PM
> Subject: Re: running! a servlet at tomcat startup
>
>
>>
>> -- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- --
>>
>> HARBOR: http://coolharbor.100free.com/index.htm
>> Now Tomcat is also a cool pojo application server
>> -- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- --
>>
>> -- -- Original Message -- -- From: "loredana loredana"
>> <loredana888888@(protected)>
>> To: "Tomcat Users List" <users@(protected)>
>> Sent: Monday, November 05, 2007 11:48 AM
>> Subject: Re: running! a servlet at tomcat startup
>>
>>
>> thanks for the response johnny. That's probably the only way it can
>> be done.. Unfortunatelly for me, I need variables like
>> request.getContextPath() and from init() method i can't "retrieve"
>> those values. 10x a lot anyway.
>> ===================================
>> Ah, I see now...
>> Yes parsing context.xml is too much hassle..
>>
>> Heres an idea...
>> When someone drops a WAR in, the context always takes on the webapp
>> name.
>> ie for most apps... webapp name = context
>> So try this...
>> ServletContext context = getServletContext();
>> String sWebBase = context.getRealPath("/");
>
> MEL just told me that context.getServletContextName()
>
> is easier ;)
Be careful! AFAIK, getServletContextName() returns "display-name" value,
not real context name - please check API!
>>
>> Than last folder is the context name...
>> Some String parsing and you got it ;)
>>
>> Good luck
>>
>> ===================================
>>
>>
>>
>> -- -- Original Message ----
>> From: Johnny Kewl <john@(protected)>
>> To: Tomcat Users List <users@(protected)>
>> Sent: Monday, November 5, 2007 10:58:54 AM
>> Subject: Re: running! a servlet at tomcat startup
>>
>>
>>
>> -- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- --
>>
>> HARBOR: http://coolharbor.100free.com/index.htm
>> Now Tomcat is also a cool pojo application server
>> -- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- ---- --
>>
>> -- -- Original Message -- -- From: "loredana loredana"
>> <loredana888888@(protected)>
>> To: <users@(protected)>
>> Sent: Monday, November 05, 2007 10:32 AM
>> Subject: running! a servlet at tomcat startup
>>
>>
>> This issue is a classic one already I think. I've googled it and
>> haven't
>> found anything that could help solving this problem. I'm probably not
>> the
>> one to think about this but...if you would add the
>> <load-on-startup>1</load-on-startup> to a servlet, and from the init()
>> method you would somehow try to call the doGet() method, wouldn't that
>> do
>> it? wouldn't that run the servlet at startup? did anybody try this
>> already?
>> I am trying to do this but I'm having some problem creating
>> HttpServletRequest and Response objects so I can call doGet(). So if
>> anyone
>> did this already, pls let me know how this issue can be fixed! 10x a
>> lot!
>> =======================
>> Hi loredana,
>> Not sure if you asking or answering ;)
>>
>> Yes, <load-on-startup> and then do stuff in the INIT method.
>> No, why try call doGet().... just init the functions that need initing,
>> like
>> the dBPool, or image processing.
>> The doGet implies you want to return info to a browser.... there isnt
>> one?
>> The Init method runs just once.... thats the idea.
>> <load-on-startup> just lets you get the INIT out of the way, otherwise
>> it
>> will happen on the first browser request, and if it takes a long time
>> the
>> browser will seem very slow to the user... but that only happens once
>> anyway.
>> ????????
>> ========================
>>
>>
>>
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