Why can 't run Sevlet in Tomcat5 2003-09-19 - By Edward King
Back
I have a servlet file,like follows:
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class a1 extends HttpServlet{
public void doGet(HttpServletResponse req,HttpServletResponse resp) throws
ServletException,IOException{
PrintWriter pw=resp.getWriter();
pw.println("<html><body>Hello World!</body></html>");
pw.close();
}
}
and web.xml is follows:
<?xml version="1.0" encoding="ISO-8859 (See http://ISO-8859.ora-code.com)-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
<servlet-name>a1</servlet-name>
<servlet-class>a1</servlet-class>
</servlet>
</web-app>
I use Tomcat5.0,I don't want to use Tomcat5 default path ,so I put a1.class
into \Tomcat 5.0\webapps\test\WEB-INF\classes,and I have added a sentence into
server.xml,like follows:
<Context path="test" docBase="test" debug="0"/>
but when I run it in IE6,like follows:
http://localhost:8080/test/servlets/a1
it raises HTTP Status 404 error,"The requested resource (/test/servlets/a1) is
not available."
Why? I have configure path! Please help.
Thanks in advance
Edward
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=Content-Type content="text/html; charset=gb2312">
<META content="MSHTML 6.00.2800.1226" name=GENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY bgColor=#ffffff>
<DIV><FONT size=2><FONT size=3>I have a servlet file,like
follows:</FONT></FONT></DIV>
<DIV><FONT size=2><FONT size=3><BR>import javax.servlet.*;<BR>import
javax.servlet.http.*;<BR>import java.io.*;<BR>public class a1 extends
HttpServlet{<BR> public void doGet(HttpServletResponse
req,HttpServletResponse resp) throws
ServletException,IOException{<BR>
PrintWriter pw=resp.getWriter();<BR>
pw.println("<html><body>Hello
World!</body></html>");<BR>
pw.close();<BR> }<BR>}<BR><BR>and web.xml is
follows:<BR><?xml version="1.0"
encoding="ISO-8859 (See http://ISO-8859.ora-code.com)-1"?><BR><BR><!DOCTYPE web-app<BR>
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application
2.3//EN"<BR> "</FONT><A
href="http://java.sun.com/dtd/web-app_2_3.dtd"><FONT
size=3>http://java.sun.com/dtd/web-app_2_3.dtd</FONT></A><FONT
size=3>"><BR><BR><web-app><BR>
<servlet><BR>
<servlet-name>a1</servlet-name><BR>
<servlet-class>a1</servlet-class><BR>
</servlet><BR></web-app><BR><BR>I use Tomcat5.0,I don't want to use
Tomcat5 default path ,so I put a1.class into \Tomcat
5.0\webapps\test\WEB-INF\classes,and I have added a sentence into
server.xml,like follows:<BR><BR><Context path="test" docBase="test"
debug="0"/><BR><BR>but when I run it in IE6,like follows:<BR></FONT><A
href="http://localhost:8080/test/servlets/a1"><FONT
size=3>http://localhost:8080/test/servlets/a1</FONT></A><BR><BR><FONT size=3>it
raises HTTP Status 404 error,"The requested resource (/test/servlets/a1) is not
available."<BR><BR>Why? I have configure path! Please help.<BR>Thanks in
advance<BR>Edward</FONT><BR></DIV></FONT></BODY></HTML>
__ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ ____ __
To unsubscribe, send email to listserv@(protected) and include in the body
of the message "signoff SERVLET-INTEREST".
<p>
Archives: http://archives.java.sun.com/archives/servlet-interest.html
Resources: http://java.sun.com/products/servlet/external-resources.html
LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
<p>
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