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org.apache.jk.common.ChannelSocket processConnection INFO: connection timeout reached
Kommineni, Sateesh (GE Consumer & Industrial)
2004-04-20
Replies:
org.apache.jk.common.ChannelSocket processConne... --
Kommineni, Sateesh (GE Consumer & Industrial)
2004-04-20
org.apache.jk.common.ChannelSocket processConne...
--
Bill Barker
2004-04-21
org.apache.jk.common.ChannelSocket processConne...
--
Thomas Tang
2004-04-20
Hi All,
I am trying to deploy a Web Application in my Tomcat and got the following Error in the Log Files..
Apr 20, 2004 11:05:04 AM
org.apache.jk.server.JkCoyoteHandler
action
INFO: RESET
Apr 20, 2004 11:05:04 AM
org.apache.jk.server.JkCoyoteHandler
action
INFO: RESET
Apr 20, 2004 11:05:14 AM
org.apache.jk.common.ChannelSocket
processConnection
INFO: connection timeout reached
What does this mean ??
I have the following entries in my server.xml.
<Connector className="
org.apache.coyote.tomcat4.CoyoteConnector
" acceptCount="10" bufferSize="2048" connectionTimeout="20000" debug="0" enableLookups="true" maxProcessors="75" minProcessors="5" address="3.130.164.201" port="12312" protocolHandlerClassName="
org.apache.coyote.http11.Http11Protocol
" proxyPort="0" redirectPort="8443" scheme="http" secure="false" tcpNoDelay="true" useURIValidationHack="false">
<Factory className="
org.apache.catalina.net.DefaultServerSocketFactory
"/>
</Connector>
<Connector className="
org.apache.coyote.tomcat4.CoyoteConnector
" acceptCount="50" bufferSize="2048" connectionTimeout="10000" debug="0" enableLookups="false" maxProcessors="75" minProcessors="20" address="3.130.164.201" port="12313" protocolHandlerClassName="
org.apache.jk.server.JkCoyoteHandler
" proxyPort="0" redirectPort="8443" scheme="ajp13" secure="false" tcpNoDelay="true" useURIValidationHack="false">
Factory className="
org.apache.catalina.net.DefaultServerSocketFactory
"/>
</Connector>
what is the significance of ajp13 scheme ??
Pls let me know.. Thanks a lot..
-Sateesh
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