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org.apache.jk.common.ChannelSocket processConnection INFO: connection timeout reached

Kommineni, Sateesh (GE Consumer & Industrial)

2004-04-20

Replies:

Hi All,

  I am trying to deploy a Web Application in my Tomcat and got the following Error in the Log Files..

   Apr 20, 2004 11:05:04 AM org.apache.jk.server.JkCoyoteHandler action
 INFO: RESET
 Apr 20, 2004 11:05:04 AM org.apache.jk.server.JkCoyoteHandler action
 INFO: RESET
 Apr 20, 2004 11:05:14 AM org.apache.jk.common.ChannelSocket processConnection
 INFO: connection timeout reached

  What does this mean ??

  I have the following entries in my server.xml.

<Connector className="org.apache.coyote.tomcat4.CoyoteConnector" acceptCount="10" bufferSize="2048" connectionTimeout="20000" debug="0" enableLookups="true" maxProcessors="75" minProcessors="5" address="3.130.164.201" port="12312" protocolHandlerClassName="org.apache.coyote.http11.Http11Protocol" proxyPort="0" redirectPort="8443" scheme="http" secure="false" tcpNoDelay="true" useURIValidationHack="false">
     <Factory className="org.apache.catalina.net.DefaultServerSocketFactory"/>
</Connector>

<Connector className="org.apache.coyote.tomcat4.CoyoteConnector" acceptCount="50" bufferSize="2048" connectionTimeout="10000" debug="0" enableLookups="false" maxProcessors="75" minProcessors="20" address="3.130.164.201" port="12313" protocolHandlerClassName="org.apache.jk.server.JkCoyoteHandler" proxyPort="0" redirectPort="8443" scheme="ajp13" secure="false" tcpNoDelay="true" useURIValidationHack="false">
Factory className="org.apache.catalina.net.DefaultServerSocketFactory"/>
</Connector>

 what is the significance of ajp13 scheme ??

Pls let me know.. Thanks a lot..

-Sateesh


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